My program should take a user inputed paragraph and check for end of sentence marker(i.e. periods, exclamations and question marks), intrasentence markers(i.e. commas, colons, semicolons), blank spaces and digits. Once it checks for these things, it should add up the number of times these things were used and them cout them to the user. My problem is that i cant figure out how to read in the digits or integers and then add them up.
I tried using an if statement but that doesn't work and im sure their is more to it. Any help would be much appreciated.



[//This program will recieve user input in the form of a paragraph and
//count the number of end sentence markers, intrasentence markers, number of spaces
//and the number of digits. It will then output this information to the user.

#include <iostream>
#include <limits>
using namespace std;

void welcome();
void getYorn(char&);

int main()
{


char para;
int numUpper = 0;
char yorn;
int smark = 0;
int imark = 0;
int blank = 0;
int dig = 0;
int sum = 0;

welcome();
getYorn(yorn);

while (tolower(yorn) == 'y')
{
cout << "Please enter a paragraph pressing enter when done: ";
cin.sync();
for (cin.get(para); para != '\n'; cin.get(para))
{
switch (para)
{
case '.':
case '!':
case '?': smark++;
break;
case ',':
case ';':
case ':': imark++;
break;
case ' ': blank++;
break;
}
if (para > 0 || para < 0 || para == 0)
{
dig++;
}
}
cout << endl;
cout << "The number of end of sentence markers is: " << smark << endl;
cout << "The number of intrasentence markers is: " << imark << endl;
cout << "The number of spaces is: " << blank << endl;
cout << "The number of digits is: " << dig << endl;
getYorn(yorn);

smark = 0;
imark = 0;
blank = 0;
dig = 0;
}
cout << "Thank you - goodbye!" << endl;
return 0;
}


void welcome()
{
cout << "Welcome to Ryan's paragraph processing information system." << endl;
cout << "This program will calculate the number of end sentence markers, " << endl;
cout << "intrasentence markers, number of spaces and number of digits within " << endl;
cout << "a paragraph. " << endl << endl;


}
void getYorn(char& yorn)
{
cout << endl;
cout << "Do you wish to continue? (y = yes, n = no) : ";
cin.sync();
cin.get(yorn);
while (tolower(yorn) != 'y' && tolower(yorn) != 'n')
{
cout << endl;
cout << "Invalid response. Do you wish to continue? ";
cin.sync();
cin.clear();
cin.get(yorn);
}



}]

Wait, so you want it to count up like the number of exclamations, question marks, etc.?

Yes exactly, and it does all that just fine. My problem is when it comes to integers. I dont know how to find or count them in the inputed paragraph. And by count, i dont mean count their actual values, i mean increment by one every time an integer is encountered.

There are multiple paragraphs, right?

This post has been edited by HKothari: 1 Dec, 2007 - 07:44 AM

No, only one paragraph because the the program quits reading when it encounters enter('\n'). Therefore, the user could only enter one paragraph.

For the case of integers you should use the condition:

Remember para is a char not an int.

Well i tried that and instead of just couting the integers, it counted every single thing inputed. I wrote a paragraph with a sum of 18 letters, spaces, integers etc.. and it outputted 18 for the integer values....... Any ideas?

here is the new code if you want to run it

[#include <iostream>
#include <limits>
using namespace std;

void welcome();
void getYorn(char&);

int main()
{


char para;
int numUpper = 0;
char yorn;
int smark = 0;
int imark = 0;
int blank = 0;
int dig = 0;
int sum = 0;

welcome();
getYorn(yorn);

while (tolower(yorn) == 'y')
{
cout << "Please enter a paragraph pressing enter when done: ";
cin.sync();
for (cin.get(para); para != '\n'; cin.get(para))
{
switch (para)
{
case '.':
case '!':
case '?': smark++;
break;
case ',':
case ';':
case ':': imark++;
break;
case ' ': blank++;
break;
}
if (para >= '0' || para <='9')
{
dig++;
}
}
cout << endl;
cout << "The number of end of sentence markers is: " << smark << endl;
cout << "The number of intrasentence markers is: " << imark << endl;
cout << "The number of spaces is: " << blank << endl;
cout << "The number of digits is: " << dig << endl;
getYorn(yorn);

smark = 0;
imark = 0;
blank = 0;
dig = 0;
}
cout << "Thank you - goodbye!" << endl;
return 0;
}


void welcome()
{
cout << "Welcome to Ryan's paragraph processing information system." << endl;
cout << "This program will calculate the number of end sentence markers, " << endl;
cout << "intrasentence markers, number of spaces and number of digits within " << endl;
cout << "a paragraph. " << endl << endl;


}
void getYorn(char& yorn)
{
cout << endl;
cout << "Do you wish to continue? (y = yes, n = no) : ";
cin.sync();
cin.get(yorn);
while (tolower(yorn) != 'y' && tolower(yorn) != 'n')
{
cout << endl;
cout << "Invalid response. Do you wish to continue? ";
cin.sync();
cin.clear();
cin.get(yorn);
}



}]

Oops! My bad. The condition should be an AND not and OR like so:


An OR will count everything except integers. Sorry.
Hope this helps

works beautifully, appreciate the help, i owe ya.

Glad I could help !