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pointers = <pointer name>**

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pointers = **<pointer name>, i cant seem to really understand what the two consecutive asterisks me

mauzinisterice	12 Dec, 2007 - 09:12 AM Post #1
New D.I.C Head Joined: 1 May, 2007 Posts: 26 My Contributions	i am new in c programming and i was blocked by this code: int main(int argc, char argv)**[i] what does this line of code means? thanks in advance!
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Martyr2	RE: Pointers = <pointer Name>** 12 Dec, 2007 - 09:37 AM Post #2
Programming Theoretician Joined: 18 Apr, 2007 Posts: 5,655 Thanked: 313 times Expert In: C/C++, Java, VB, VB.NET, C#, PHP, Web Development, HTML & CSS, Javascript My Contributions	Hi mauzinisterice, When you start an application from something like the command line (dos prompt for example) you can pass it parameters. The number of parameters goes in argc (representing argument count) and the actual arguments go in argv (argument values). So for instance if I start the application like so... CODE run myapp.exe c:/test.txt d:/test2.txt argc will equal 2 and argv[0] will contain c:/test.txt and argv[1] will contain d:/test2.txt. The double asterisks mean that it is a pointer to an array of character strings which are pointers themselves. So it is a pointer to an array of character string pointers. I suggest you read up on the use of pointers and perhaps this will make more sense.
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mauzinisterice	RE: Pointers = <pointer Name>** 12 Dec, 2007 - 10:04 AM Post #3
New D.I.C Head Joined: 1 May, 2007 Posts: 26 My Contributions	thanks! that helped me a lot!
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