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Counting numbers in an integer

 
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Counting numbers in an integer
janandrada
5 Jan, 2008 - 06:53 AM
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how can a program counts the number in an inputted integer?
ie, input: 24854203
output: 8 numbers

here's my code:
CODE

int x;

cout << "Input an integer: ";
cin >> x;

int y = 0;
for(int i = 1; i < 10; i++){
    if(y <= x)
}
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PennyBoki
RE: Counting Numbers In An Integer
5 Jan, 2008 - 07:03 AM
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system("revolution");
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Well a hint would be:
use the div operator that is / in your loop. So while x div 10 is different than 0 counter++.
Then just print the counter+1.

Hope this helps.
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Amadeus
RE: Counting Numbers In An Integer
5 Jan, 2008 - 07:04 AM
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g++ -o drink whiskey.cpp
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Another method would be to take the input as a string, then manipulate it, perhaps using the .length() method. Especially given that you may overflow the size of the int variable getting untested user input.
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DPR
RE: Counting Numbers In An Integer
5 Jan, 2008 - 12:29 PM
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The best way I can think of within about 10 seconds and without detailed thought would be to simply divide by ten and floor the result (maintaining it's integer-ness), and add a number to a counter each iteration.
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jjhaag
RE: Counting Numbers In An Integer
5 Jan, 2008 - 02:48 PM
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Using floor() is not necessary; integer division results in the truncation of any non-integral component of the quotient.
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